popularityEqualTo method

QueryBuilder<DictionaryEntry, DictionaryEntry, QAfterWhereClause> popularityEqualTo(
  1. double popularity
)

Implementation

QueryBuilder<DictionaryEntry, DictionaryEntry, QAfterWhereClause>
    popularityEqualTo(double popularity) {
  return QueryBuilder.apply(this, (query) {
    return query.addWhereClause(IndexWhereClause.equalTo(
      indexName: r'popularity',
      value: [popularity],
    ));
  });
}